PEMBAHASAN
SOAL 1
Menentukan hambatan pengganti
[tex] \frac{1}{Rp} = \frac{1}{16 + 8} + \frac{1}{6} [/tex]
[tex] \frac{1}{Rp} = \frac{1}{24} + \frac{1}{6} [/tex]
[tex] \frac{1}{Rp} = \frac{1 + 4}{24} [/tex]
[tex] \frac{1}{Rp} = \frac{5}{24} [/tex]
[tex] \frac{Rp}{1} = \frac{24}{5} [/tex]
[tex]Rp = 4,8 \: ohm[/tex]
R = 4,8 ohm
Menentukan tegangan listrik
R = 4,8 ohm
I = 2 A
[tex]V = I \: . \: R[/tex]
[tex]V = 2 \: A \: . \: 4,8 \: ohm[/tex]
[tex]V = 9,6 \: V[/tex]
SOAL 2
Menentukan hambatan pengganti
karena itu hambatan paralelnya 2 maka cari 1 1
[tex] \frac{1}{Rp} = \frac{1}{8} + \frac{1}{2} [/tex]
[tex] \frac{1}{Rp} = \frac{1 + 4}{8} [/tex]
[tex] \frac{1}{Rp} = \frac{5}{8} [/tex]
[tex] \frac{Rp}{1} = \frac{8}{5} [/tex]
[tex]Rp = 1,6 \: ohm \: (ke \: 1)[/tex]
[tex] \frac{1}{Rp} = \frac{1}{6} + \frac{1}{4} [/tex]
[tex] \frac{1}{Rp} = \frac{2 + 3}{12} [/tex]
[tex] \frac{1}{Rp} = \frac{5}{12} [/tex]
[tex] \frac{Rp}{1} = \frac{12}{5} [/tex]
[tex]Rp = 2,4 \: ohm \: (ke \: 2)[/tex]
R = 1,6 ohm + 2,4 ohm
R = 4 ohm
Menentukan kuat arus
R = 4 ohm
V = 20 V
[tex]I = \frac{V}{R} [/tex]
[tex]I = \frac{20 \: V}{4 \: ohm} [/tex]
[tex]I = 5 \: A[/tex]
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